Question

1. A body slipping on a rough horizontal plane moves with
a deceleration of 4.0 m/s". What is the coefficient of
kinetic friction between the block and the plane ?
nalang.
h horizontal rood with​

Answer 1

Answer:

Let m be the mass of that body

R − mg = 0

Where R is the normal reaction force and g is the acceleration due to gravity

R = mg       - - - - - -----(1)

ma − μkR = 0

(where μk is the coefficient of kinetic friction and a is deceleration)

ma = μkR

From Equation (1),

ma =  μkmg

a = μkg

4 = μkg

μk=4g=410=0.4

⚫Hence, the coefficient of the kinetic friction between the block and the plane is 0.4.

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