Physics, asked by krishndwivedi, 1 year ago

1. A body starts from rest with a uniform acceleration
of 2 m s-2. Find the distance covered by the body
in 2 s.
OF Ans. 4 m​

Answers

Answered by Anonymous
4

Answer:

s=4m

Explanation:

according to Newton 's second law of motion,

s=ut+1/2 at^2

u=0 because the body starts from rest with a uniform acceleration.

s= 1/2 at^2

s= 1/2 2×4

s=4m

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Answered by Nereida
19

Answer:

The Initial velocity of the body = 0 m/s.

The uniform acceleration of the body = 2 m/s².

Time taken = 2 s.

Finding the final velocity of the body :

⇒ a = v - u/t

⇒ 2 = v - 0/2

⇒ v = 4 m/s

Finding the distance covered by the body :

⇒ s = ut + ½at²

⇒ s = 0*2 + ½*2*2²

⇒ s = 0 + 2²

⇒ s = 4 m

Hence, the distance travelled by the body in 2 s = 4 m.

Important Formulas :

  • v = u + at
  • s = ut + ½at²
  • v² - u² = 2as
  • V_BA = V_B - V_A
  • V_AB = V_A - V_B
  • Instantaneous velocity = dx/dt
  • Instantaneous acceleration = dv/dt

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