Question

1.
A body starts from rest with a uniform acceleration
of 2 m s-2. Find the distance covered by the body
in 2 s.
Ans. 4 m​

Answer 1

$\huge{\underline{\underline{\red{\mathfrak{Answer :}}}}}$

$\tt Given \begin{cases} \sf{Acceleration(a) \: of \: the \: object \: is \: 2ms^{-2}} \\ \sf{Time(t) \: taken \: by \: the \: body \: is \: 2s} \end{cases}$

_____________________________

To Find :

$\hookrightarrow \sf{Distance(s) \: covered \: by \: the \: body}$

_____________________________

Solution :

We know that,

$\large{\star{\underline{\boxed{\sf{s = ut + \frac{1}{2} at^2}}}}}$

Here, we will use initial velocity (u) as 0. Because the object is started from the rest.

(Putting Values)

$\rightarrow \: \sf{s = 0(2) + \frac{1}{2}(2) {(2)}^{2} } \\ \\ \sf{s = 0 + \frac{1}{ \cancel2} \times \cancel 2 \times 4} \\ \\ \sf{s = 4 \: m}$

$\large{\star{\underline{\boxed{\sf{Distance (s) = 4 \: m}}}}}$

$\rule{200}{2}$

Verification :

For verification of the distance that distance is wrong or right then put value of distance

$\rightarrow \: \sf{4 = 0(2) + \frac{1}{2}(2) {(2)}^{2} } \\ \\ \sf{4= 0 + \frac{1}{ \cancel2} \times \cancel 2 \times 4} \\ \\ \sf{4 \:m = 4 \: m}$

Hence Verified

__________________________

Equation of motion :

• v = u + at

• S = ut + 1/2at^2

• v^2 - u^2 = 2as

$\rule{200}{2}$

#answerwithquality

#BAL