Question

1. A body starts moving from rest with an acceleration of 4ms-2 . Find its velocity after 4second.​

Answer 1

Answer:

Velocity after 4 second of body i.e., final velocity of body (v) is 16 m/s .

Explanation:

Given,

A body starts at rest i.e.,

u = 0 m/s

t = 4 second

a = 4 m/s^2

By using the formula of 1 st equation of motion

we get,

v = u + at

v = 0 + 4 × 4 m/s

v = 0 + 16 m/s

v = 16 m/s

Here,

u is the initial velocity of body.

v is the final velocity of body.

a is the acceleration of the body.

t is the time taken by body.

Hence,

Velocity after 4 second of body i.e., final velocity of body (v) is 16 m/s .

Answer 2

Explanation:

$\pink{\large{\underline{\underline{\sf Given:-}}}}$

• $\sf \blue{Velocity_{\red{initial}}}=0$
• $\sf \blue{Acceleration}=4\: m/s^2$
• $\sf \blue{Time}=4 \: s$

$\pink{\large{\underline{\underline{\sf To \: find:-}}}}$

• $\sf \blue{Velocity_{\red{final}}}=0$

$\pink{\large{\underline{\underline{\sf Solution:-}}}}$

$\sf \bf We \: Know \: that,$

$\underline{\boxed{\sf v = u+at}} \gray\bigstar$

$\longmapsto 0+4×4$

$\longmapsto \underline{\boxed{\sf \bf v = 16 \: m/s}}$