Question

1. A body with mass 2 kg absorbs heat 100 calorie when its temperature raises from 20°C
to 70°C. What is the specific heat of the body?​

Answer 1

Answer:-

Given:

Mass of the body (m) = 2 kg = 2 × 1000 g = 2000 g.

Heat absorbed (Q) = 100 cal

Initial Temperature = 20° C

Final temperature = 70° C

We know that,

Specific heat (S) = Q / m ∆ T

So,

⟶ S = 100/ 2000 (70 - 20)

⟶ S = 100 / 2000 (50)

⟶ S = 1/1000 cal / g * °C

⟶ S = 10⁻³ cal/g * °C

∴ The specific heat of the body is 10⁻³ cal/g * °C.

Answer 2

Answer is given below :)

Given that ,

• Mass of the body = 2 kg = 2 × 1000 g = 2000 grams.
• Heat observed = 100
• CalInitial temperature = 20°C
• Final temperature = 70°C

We know that,

Specific heat = Q/m∆TSo,

➡ S = 100/2000 (70-20)

➡ S = 100/2000 (50)

➡ S = 1/1000 cal/g × °C

➡ S = 10-³ cal/g × C°

Therefore, The specific heat of the body is 10-³ cal/g ×C°

Hope it's helpful

Thank you :)