Question

1 A book exhibition was held for four days in a school. The number of tickets soli
at the counter on the first second third and final day was respectively 1094
1812. 2050 and 2751. Find the total number of tickets sold on all the four days​

Answer 1

Answer:

Step-by-step explanation:

tickets sold on first day = 1094

tickets sold on second day = 1812

tickets sold on third day = 2050

tickets sold on fourth day =  2751

total tickets sold on four days = add the nos.

= 1094  + 1812 + 2050 + 2751

= 7707 tickets

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Answer 2

Number of tickets sold on 1st day = 1094

Number of tickets sold on 2nd day = 1812

Number of tickets sold on 3rd day = 2050

Number of tickets sold on 4th day = 2751

Hence, number of tickets sold on all the four days = 1094 + 1812 + 2050 + 2751 = 7707 tickets