Question

1,A box contains 5 red balls, 4 blue balls and 7 green balls. A ball is drawn at random from box.the probability that the drawn ball is neither red nor green is
2.A single letter is selected from word "PROBABILITY". The probability that the letter is a vowel is

Answer 1

(1) No of red balls=5
No of blue balls=4
No of green balls=7
Total no of balls=5+4+7=16
The balls which are neither red nor green are blue balls that are 4 in number
Probability=no of favourable outcomes/total no of outcomes=4/16=1/4
(2)total no of letters =11
No of vowels=4
Probability of getting a vowel=4/11

Answer 2

1 )  p(E) =favourable outcome / total outcomes.

neither red nor green = 4 blur balls only (because no red or green)
so favourable outcome =4
total = 5 + 4+ 7 = 16
 p(E) =4/16 = 1/4

 p(E)= 1/4

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2 ) PROBABILITY has 11 letters.
vowel = 4 ( O, A , I, I)
total =11

 p(E) =favourable outcome / total outcomes.

 p(E) = 4/11




hope it helps!!!!