Question

1. A box is of dimensions 2.4 m x 1-0 m
x 75 cm. Find the volume of the box.
Given : length 1 = 2.4 m, breadth b = 1.0 m
and height h = 75 cm = 0.75 m.
Volume of box V = lxbxh​

Answer 1

${ \tt{ \large \bold{ \purple{given}}}}$

${ \rm{the \: dimensios \: of \: a \: box \: are \to}}$

${ \rm{length(l) = 2.4m}}$

${ \rm{breadth(b) = 1.0m}}$

${ \rm{volume(v) = 0.75m}}$

${ \tt{ \large \bold { \blue{solution}}}}$

${ \rm{ volume(v) = l \times b \times h}}$

${ \rm{ = 2.4 \times 1.0 \times 0.75 \: {m}^{3} }}$

${ \rm{ = 1.8 {m}^{3} }}$

${ \rm {Ans \colon \:so \: the \: volume \: is \: 1.8 {m}^{3} }}$

──────────────────────────

${ \rm{ \large{related \: formulas}}}$

${ \rm{ \large{Perimeter \colon}}}$

${ \rm{perimeter \: of \: square =4a }}$

${ \rm{perimeter \: of \: rectangle =2(l + b) }}$

${ \rm{perimeter \: of \: triangle =a + b + c }}$

${ \rm{perimeter \: of \: circle=2 \pi r}}$

${ \rm{ \large{Area \colon}}}$

${ \rm{area \: of \: square = {a}^{2} }}$

${ \rm{area \: of \: rectangle =l \times b }}$

${ \rm{area\: of \: triangle = \frac{{h_b}b}{2} }}$

${ \rm{area\: of \: circle = \pi \: {r}^{2} }}$

${ \rm{ \large{Volume \colon}}}$

${ \rm{volume \: of \: cube = {a}^{3} }}$

${ \rm{volume \: of \: cuboid = l \times b \times h }}$

${ \rm{volume \: of \: cylinder = \pi {r}^{2}h }}$

${ \rm{volume \: of \: cone = \frac{1}{3} \pi {r}^{2}h }}$

Answer 2

$\large\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

$\tt\large{\red{Given -}}$

The dimesion of a box are$\dashrightarrow$

lengh ( l )= 2.4m

breath ( b ) = 1m

hieght ( h )= 0.75 m

$\textbf{\large{\red{Solution}} }$

Volume ( v ) $\dashrightarrow$$l \: \times \: b \: \times \: h$

$\dashrightarrow$ 2.4 * 1 * 0.75 .

$\dashrightarrow$ $\tt\large{\red{1.8 \: m^3}}$( meter cube )

$\tt\large{\red{Hence \: volume \: of \: cube \: is \: 1.8 m^3}}$