Question

1. A boy bought some storybooks costing ? 48 each
and some picture books costing
* 32 each, spending 912 in all.
If the number of picture books he
bought is two-fifths of the number
of storybooks, how many of each
did he buy?​

Answer 1

Answer:

No. of story books = 15

No. of picture books =6

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Step-by-step explanation:

Let the no. of story books bought be

$x$

and the no. of picture books bought be

$y$

Money spent on buying story books =

$48x$

Money spent on buying picture book =

$32y$

According to the question

$48x + 32y = 912 - - - - eq^{n} 1$

Also,

$y = \frac{2}{5} x \: - - - - - - - eq^{n} 2$

Substituting eq 2 in 1

$48x + 32 \times \frac{2}{5} x = 912$

$48x + \frac{64}{5} x = 912$

$\frac{(240 + 64)}{5} x = 912$

$304x = 912 \times 5$

$x = \frac{4560}{304}$

$x = 15$

$= = > y = \frac{2}{5} \times 15$

$y = 6$

Answer 2

Step-by-step explanation:

Answer:

No. of story books = 15

No. of picture books =6

HOPE IT HELPS.

PLS MARK AS BRAINLIEST!!

Step-by-step explanation:

Let the no. of story books bought be

xx

and the no. of picture books bought be

yy

Money spent on buying story books =

48x48x

Money spent on buying picture book =

32y32y

According to the question

48x + 32y = 912 - - - - eq^{n} 148x+32y=912−−−−eqn1

Also,

y = \frac{2}{5} x \: - - - - - - - eq^{n} 2y=52x−−−−−−−eqn2

Substituting eq 2 in 1

48x + 32 \times \frac{2}{5} x = 91248x+32×52x=912

48x + \frac{64}{5} x = 91248x+564x=912

\frac{(240 + 64)}{5} x = 9125(240+64)x=912

304x = 912 \times 5304x=912×5

x = \frac{4560}{304}x=3044560

x = 15x=15

= = > y = \frac{2}{5} \times 15==>y=52×15

y = 6y

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