Question

1.
A boy is moving along a square path ABCDA is as
shown in figure. If the boy is taken 5 sec time to
travel any side of the square, Then find average velocity along A to B
average velocity along path ABC
average velocity along ABCD.
Average speed along ABCDA​

Answer 1

Answer :

Time taken by boy to travel any side of the square = 5s

★ Average velocity is defined as the ratio of total displacement to the total time.

It is a vector quantity having both magnitude as well as direction$.$

SI unit : m/s

(A) Av. velocity along A to B :

• Displacement = 5 m
• Time = 5 s

➝ Vav = 5/5

➝ Vav = 1 m/s

(B) Av. velocity along path ABC :

• Displacement = 5√2 m
• Time = 2 × 5 = 10 s

➝ Vav = 5√2/10

➝ Vav = √2/2

➝ Vav = 1/√2 m/s

(C) Av. velocity along path ABCD :

• Displacement = 5 m
• Time = 3 × 5 = 15 s

➝ Vav = 5/15

➝ Vav = 1/3

➝ Vav = 0.33 m/s

(D) Av. velocity along path ABCDA :

• Displacement = 0 m
• Time = 4 × 5 = 20 s

➝ Vav = 0/20

➝ Vav = 0 m/s