Question

1. A boy weighing 600 N sits on the see-saw at a distance of 1.5 m from the pivot. What
is the force F required at the other end (2 m away) to balance the see-saw??​

Answer 1

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Answer 2

The Force (F) required at the other end (2 m away) to balance the see-saw is 450 N.

According to the question,

• The weight of the boy (F1) = 600 N

• Distance of the boy from the pivot (r1) = 1.5 m

• Distance of Force F from the pivot (r) = 2m
• The distance of force F from pivot = r

Using the formula,

F × r = F1 × r1

F × 2 = 600 × 1.5

F = (600 × 1.5) ÷ 2

F = 450 N

Thus, the answer is 450 N