Question

1.] A brick is kept in two different ways on table as shown in figure the pressure exerted by brick on the table will be

a) Maximum in position A

b) Maximum in position B

c) Minimum in position A

d) Equal in all cases​

Answer 1

Answer:

Given:

A brick is kept in 2 different ways on a table as shown below.

To find:

The pressure exerted by the brick on the table will be?options are:- 1) maximum in positionA. (2) maximum in position B (3) equal in both cases

Solution:

From given, we have,

A brick is kept in 2 different ways on a table as shown below.

Consider the attached figure while going through the following steps.

From the figure, it's clear that,

In the case of brick A, the pressure applied is verticle (perpendicular).

In the case of brick B, the pressure applied is horizontal (parallel).

We know that the perpendicular pressure is always greater than the parallel pressure.

Thus the pressure exerted by the brick on the table will be 1) maximum in position A.

Answer 2

Answer:

a) Maximum in position A