Question

(1)
A bucket is frustum shaped. Its height is 28 cm. Radii of circular faces are
12 cm and 15 cm. Find the capacity of the bucket. ( n =22/7 )​

Answer 1

Radius of upper part of the bucket(R) = 28 cm

Radius of Lower part of the bucket(r)= 7 cm

Volume of the bucket = 1/3πh( R²+r²+Rr)

21560 = 1/3×22/7×h[(28)² + (7)² + 28×7)]

21560 = 1/3×22/7×h[ 784+49+196]

21560 = 1/3×22/7×h(1029)

21560 = 1/3×22/7× 1029H

H = 21560×3×7/22638

H = 452760/22638

H = 20 cm.

Slant height (L) = ✓(h)²+(R-r)²

= ✓(20)² + (28-7)²

= ✓400+441 = ✓841 = 29 cm

THEREFORE,

TSA of bucket = CSA of bucket + Area of Lower part of the bucket

= πL(R+r) + πr²

Putt the all values and solve.. you will get the TSA of bucket..

hope it helps

please mark as BRAINLIEST

Answer 2

Answer:

Hope helps u

Step-by-step explanation: