1. A bus decreases its speed from
SO km h to 60 km h- in 5 s.
Find the acceleration of the bus.
2. A train starting from a railway
station and moving with uniform
acceleration attains a speed
40 km h-l in 10 minutes. Find its
acceleration
Answers
Answer:
ans -1.11m/sec^2
Explanation:
Initial speed of bus, u = 80 km/hr
= 80 * 1000 / 3600 m/s
=800/36 m/s
Final speed of bus, v = 60 km/hr
60 * 1000 / 3600 m/s
=600 / 36 m/s
Therefore,
Acceleration, a = (v-u) /t
= ( (600/36) - (800/36) ) / 5
= -10/9 m/s^2
= -1.11 m/s^2
Answer:
1)
Explanation:
a = acceleration
u = initial velocity
v = final velocity
t = time
1) v = 60 km/h
t = 5s
so, to convert km/h into m/s multiply with 5/18
60×5/18
16.7 m/s (approximately)
v = 16.7 m/s
u = 0m/s. [ because the object is started from rest ]
a = v - u / t
= 16.7 - 0 / 5
a = 3.36 m/s ^(2)
2) v = 40km/h
t = 10m
so, to convert km/h into m/s multiply with 5/18
v = 40 × 5 / 18
= 2.3m/s
to convert minute into second multiply with 60s
t = 10 × 60 = 600s
u = 0 m/s [ because the object is started from rest ]
a = v - u / t
= 2.3 - 0 / 600
a= 0.0039m/s^(2)
HOPE IT HELPS YOU