Question

1.A bus starting from rest moves with a uniform acceleration of 0.1m s-² for 2minutes. find (a) the speed acquired, (b) the distance travelled ​

Answer 1

A bus starting from rest, means the initial velocity of the bus is 0 m/s and moves with a uniform acceleration of 0.1 m/s² for 2 min.

We have to find the speed and distance travelled by the bus.

a) For speed

Firstly convert the minutes into seconds. To do this multiply the given value by 60.

1 min = 60 sec

2 min = 120 sec

Using the First Equation Of Motion

v = u + at

Substitute the known values,

→ v = 0 + 0.1(120)

→ v = 0 + 12

→ v = 12

Therefore, the final velocity of the bus is 12 m/s.

b) For distance travelled

Using the Second Equation Of Motion

s = ut + 1/2 at²

Substitute the values,

→ s = 0(120) + 1/2 × 0.1(120)²

→ s = 0 + 0.05(14400)

→ s = 720

Therefore, the distance travelled by the bus is 720 m.

Answer 2

Answer: distance = 0.5*0.1*2*2*60*60 metres

720m

Speed = 0.1*2*60

12m/s

Explanation:

Speed = u+a*t

Distance = u*t+0.5*a*t²