Question

1. A bus starting from rest moves
with a uniform acceleration of
0.1 ms2 for 2 minutes. Find (a)
the speed acquired, (b) the
distance travelled.​

Answer 1

Answer:

Step-by-step explanation:a=0.1m/s  

2

 

and t=2min=120s

(A)v=u+at=0+0.1×120

⟹v=12m/s

(b)s=ut+  

2

1

​  

at  

2

 

⟹s=0+  

2

1

​  

×0.1×(120)  

2

 

⟹s=720m

Answer 2

$\bf{\underline{Given}}:-$

• Acceleration (a) = 0.1 m/s²

• Time (t) = 2 min = 120 sec

• Initial velocity (u) = 0 m/s

$\bf{\underline{To\:Find}}:-$

• The speed aquired = ?

• The distance travelled = ?

$\bf{\underline{Solution}}:-$

$\small\gray{\bigstar}\:\:{\underline{\boxed{\bf\purple{Using\:{1}^{st}\:equation\:of\:motion}}}}$

$\blue{\bigstar}\:\:{\underline{\boxed{\bf\pink{v=u+at}}}}$

$\rm\longrightarrow\:v=0+0.1\times\:120$

$\rm\longrightarrow\:v=0.1\times\:120$

$\rm\longrightarrow\:v=12\:m/s$

Now,

$\small\orange{\bigstar}\:\:{\underline{\boxed{\bf\blue{Using\:{3}^{rd}\:equation\:of\:motion}}}}$

$\red{\bigstar}\:\:{\underline{\boxed{\bf\orange{{v}^{2}={u}^{2}+2as}}}}$

$\rm\longrightarrow\:{(12)}^{2}={(0)}^{2}+2\times\:0.1\times\:s$

$\rm\longrightarrow\:144=2\times\:0.1s$

$\rm\longrightarrow\:\dfrac{144}{0.2}=s$

$\rm\longrightarrow\:720=s$

$\rm\longrightarrow\:s=720\:m$

Hence,the speed aquired = 12 m/s and the distance travelled = 720 m.

$\pink{\bigstar}\:\:{\underline{\boxed{\bf\green{More\:Information}}}}$

➝ Speed :- It is defined as the distance covered by per unit time.

• SI unit of speed is m/s.
• CGS unit of speed is cm/s.
• It is a scaler quantity.
• It is always positive.

➝ Distance :- It is defined as the actual path length covered by moving object.

• SI unit of distance is m.
• CGS unit of distance is cm.
• It is a scaler quantity.
• distance is always positive.