Question

а
1. A bus starts from rest and attains 40 km h-1 velocity after 10 seconds. Calculate the acceleration of the bus
(Ans. (i) 14400 km h-2 (ii) 1.11 m
2. A bus moving with a velocity of 60 km h-1 is brought to rest in 20
(1) km h-2 and (ii) m 5-2​

Answer 1

Answer:

We know,

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time

t = 10 sec = 10/3600 hr

40 = 0 + a*(1/360)

a = 40*360 = 14400 km/hr^2

In m/s^2

a = 14400 * 1000/(3600*3600)

= 14400 * (1/18*720)

= 1.11 m/s^2