Question

1.(a) Calculate the KE of a photo electron emitted by sodium surface when light
of wavelength 400 nm is incident on it. The work function of sodium is 3.653
x10-19 J.
​

Answer 1

Explanation:

Solution :

(a)hυ=hυ0+KE where hυ0=ϕ=2.28eV

⇒KE=hυ−hυ0=−2.28eV+1240400eV=0.82eV

(b) For max λ,KE=0

⇒hcλmax=ϕ⇒1240λmax=2.28

λmax=544nm