Math, asked by Gursewak2388, 11 months ago

1. A can do a work in 14 days and working together a and b can do the same work in 10 days. In what time can b alone do the work?

Answers

Answered by ayushikarn7
4

Answer:

1 day work of A=1/14

1 day work of (A+B)=1/10

Given:A+B=1/10

or,1/14+B=1/10

or,B=1/10-1/14

Or,B=2/70=1/35

Now, 1/35 part of work is done in 1 day by B.

So,1 work will be done in 1÷1/35=35 days.

B can alone do the work in 35 days.

Answered by Anonymous
2

A can complete the work in 14 days

So, A's 1 day's work = 1/14

A and B can complete the same work in 10 days

So, A and B 1 day's work = 1/10

Let the days taken to complete the same work By B be x

B's 1day work = 1/x

Equation formed :

 \frac{1}{10}  -  \frac{1}{14}  =  \frac{1}{x}

 \frac{1 \times 7}{10 \times 7}  -  \frac{1 \times 5}{14 \times 5}  =  \frac{1}{x}

 \frac{7}{70}  -  \frac{5}{70}  =  \frac{1}{x}

 \frac{2}{70}  =  \frac{1}{x}

 \frac{70}{2}  =  x

x = 35

So, B alone can do the same work in 35 days.

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