Question

1.A car accelerates uniformly from 18km/h to 36km/h in 5s.Calculate the acceleration and distance coverd by the car in that time​

Answer 1

Answer:

ACCELERATION =V-U/T

a = 36-18/5

= 18/5

= 3.6 m/s^2

DISTANCE = UT +1/2 AT^2

= 18×5+1/2×3.6×5×5

=90+45

= 135 meters