Question

1. A car having mass 700 kg is moving at a speed of 90 km/hr. on applying brakes
speed is reduced to 36 km/hr, in 10s. Calculate the force applied by the brakes.
Pls answer fast...Its urgent. Love ya​

Answer 1

Answer:

m= 700 kg

u= 90 km/hr = 90 * 5/ 18 m/s = 25 m/s

v = 36 km/hr = 30 * 5/18 m/s = 10 m/s

t = 10s

a = ?

F = ?

a= (v-u) /t

a = (10 - 25) / 10

a = -15/10 = -1.5 m/s ²

negative sign means car is retarding

we know that Force = mass * acceleration

so, 700 * ( - 1.5)

F = -1050 N

therefore ∴ the force applied by the brakes is 1050 N in the opposite direction .

hope it helps =)

pls thumbs up

Answer 2

Answer:

Force applied = -1050 N

Explanation:

mass = 700kg

initial velocity = 90km/h = 25m/s

final velocity = 36km/h = 10m/s

time = 10s

acceleration = v - u/t

acceleration = 10-25/10

acceleration = -1.5m/s²

Force = mass × acceleration

Force = 700 × (-1.5)

Force = -1050 N