Math, asked by jashwanthreddy1811, 9 months ago

1
A car is travelling on a straight road. The maximum velocity the car can attain is 24 ms The maximum acceleration and deceleration it can attain are 1 m/s2 and 4m/s2
respectively. The shortest time the car takes to start from rest and come to rest in a distance of 200 metre is
ms
and 4 ms-2​

Answers

Answered by bhimraokharat30
0

Answer:

S=ut+1/2at^2

200=(0)(t)+1/2(4)(t)^2

200=2(t)^2

200/2=(t)^2

100=t^2

t=10

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