1
A car is travelling on a straight road. The maximum velocity the car can attain is 24 ms The maximum acceleration and deceleration it can attain are 1 m/s2 and 4m/s2
respectively. The shortest time the car takes to start from rest and come to rest in a distance of 200 metre is
ms
and 4 ms-2
Answers
Answered by
0
Answer:
S=ut+1/2at^2
200=(0)(t)+1/2(4)(t)^2
200=2(t)^2
200/2=(t)^2
100=t^2
t=10
Similar questions