1.a car moves with constant speed of 10 m/s in a circular path of radius 10 m. the mass of the car is 1000 kg. who or what is providing the required centripetal force for the car ? how much is it ?
2. the bob of the pendulum of length 1m has mass 100g and a speed of 1.4 m/s at the lowest point in its path. find the tension in the string at this moment.
Answers
Answered by
4
1. The centripetal force is provided by the engine which supplies energy to the wheels and creates momentum.
Centripetal force =
Centripetal force = 1000 × 10² ÷ 10
Centripetal force = 10000N
2. T - mg = mv² ÷ r
T = mv² ÷r + mg
T= 0.1kg × 1.4² ÷1 + 0.1 × 10
T = 0.1 × 1.96 + 1
T = 0.196 + 1
T = 1.196N
Centripetal force =
Centripetal force = 1000 × 10² ÷ 10
Centripetal force = 10000N
2. T - mg = mv² ÷ r
T = mv² ÷r + mg
T= 0.1kg × 1.4² ÷1 + 0.1 × 10
T = 0.1 × 1.96 + 1
T = 0.196 + 1
T = 1.196N
fluffy:
thank u so much for the answers :)
Answered by
0
Answer:
Centripetal force, F=10^4\ NF=10
4
N
Explanation:
Given that,
Speed of the car, v = 10 m/s
Radius of the circular path, r = 10 m
Mass of the car, m = 1000 kg
Let F is the centripetal force required for this car. Mathematically, it is given by :
F=\dfrac{mv^2}{r}F=
r
mv
2
F=\dfrac{1000\times (10)^2}{10}F=
10
1000×(10)
2
F=10^4\ NF=10
4
N
So, the centripetal force required for this car is 10^4\ N10
4
N . Hence, this is the required solution.
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