1. A car moving along in a straight highway from point P to point Q to point R and to point S, then back to point Q and finally to the point R as shown in the figure below.
a) Find the distance travelled by car.
b) Find the displacement of the car
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Explanation:
(a) As the car goes from O to P:
Since the car moves in a straight line, the distance will be equal to the displacement.
Total distance = Total displacement=360
The time taken by the car is=18 sec
Average speed of car is given by:
vavg=Total time takenTotal distance
=18360=20 m/s
Average velocity of the car is given by:
=Total time takenTotal displacement
=18360=20 m/s
(b)As the car goes from O to P and then back to O:
Total distance covered by car =360+(360−240)=360+120=480 m
The total displacement of car =240 m
Total time taken =18+6=24 sec
Average speed
=24480=20 m/s
Average velocity
=24240=10 m/s
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