Question

1. A car of mass 1000kg is moving up a hill inclined at 300 to the horizontal. Given that the total friction force on the car is 1000N, calculate the force (P) of the engine when the car is;

i) Accelerating upwards at 4m/s²?
ii) Moving with a steady speed of 15m/s?

Answer 1

Answer:

Here is the Answer : -

Explanation:

Situation -1

Mass of the Car - 1000kg

Accelaration - 4ms^-2

Force = Mass x Accelaration

Force = 1000kg x 4ms^-2

Force = 4000 Newton

Frictional Force = 1000 Newton

Net Force = 4000 Newton - 1000 Newton

= 3000 Newton

Situation - 2

Mass of the Car - 1000kg

Accelaration - 0ms^-2

Force = Mass x Accelaration

Force = 1000kg x 0ms^-2

Force = 0 Netwon

Net Force = 0 Netwon - 1000 Netwon

= -1000 Newton