Question

1. A car of mass 500kg is
moving with a speed of 10m/s
on a level road. Calculate the
retarding force required to
stop the car in a distance of
50m?​

Answer 1

Answer:

Explanation:

◆ Answer-

F = -1000 N

◆ Explanation-

# Given-

m = 1000 kg

u = 36 km/hr = 10 m/s

v = 0

s = 50 m

# Solution-

Using Newton's 3rd kinematic eqn,

v^2 = u^2 + 2as

0 = 10^2 + 2×a×50

a = -100/100

a = -1 m/s^2

Retarding force is calculated by-

F = -ma

F = -1000 × 1

F = -1000 N

Therefore, retarding force is 1000 N in magnitude.

Hope this helps.