Question

1. A car starts from rest and accelerates uniformly for 5 seconds. If it covers 200 m
in this duration, find its acceleration and final velocity.
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Answer 1

u=0

t=5sec

d=200m....

speed=d/t=200/5=40m/sec

so v=40m/sec

now acceleration i.e a=v-u/t=40-0/5=8m/sec.

Answer 2

Answer:

initial velocity (u)=0 m/s²

time(t)= 5 seconds

distance (s)=200m

s = ut+ 1 at²

2

200= 0×5 + 1 × a×(5)²

2

200=0+ 1 25a²

2

200=25a

2

a= 200×2

25

a=16m/s2

v=u+at

0+16×5

80m/s