1. A car starts from rest and travels a distance s with a
uniform acceleration f; then it travels with uniform
velocity for a time t; and at last comes to rest with a
uniform retardation . If the total distance travelled is
5 s. Then
A) S=ft
B)S=0.2ft
C)S=0.25ft
D)S=1/6ft
Answers
Answer:
et initial distance traveled by the car is s
1
, in time t
1
, and velocity is v
1
then
s
1
=
2
1
αt
1
2
v
1
=αt
1
v
1
2
=2αs
1
let remaining distance traveled by the car is s
2
, in time t
2
, and velocity is v
2
then
Now, u
2
=v
1
So, s
2
=v
1
t
2
−
2
1
βt
2
2
v
2
=0=αt
1
−βt
2
⇒
t
2
t
1
=
α
β
t
1
+t
2
=t⇒t
2
(
α
β
+1)=t⇒t
2
=
β+α
αt
So, t
1
=(
β+α
βt
)
Clearly maximum velocity attained is v
1
, so
v
1
=αt
1
=(
β+α
αβt
)
Explanation:
this answers is wrong this answer is copy paste from Google because such a big explaination is this it's fake