1) A car starts from rest. If the acceleration of the car is 2.5 m/s2, What will be its velocity at the end of 10 seconds and what distance will it cover during that time?
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Given :-
A car starts from rest. If the acceleration of the car is 2.5 m/s²
To Find :-
What will be its velocity at the end of 10 seconds and what distance will it cover during that time?
Solution :-
As it starts from rest then initial velocity will be 0 m/s
v = u + at
Where
v = final velocity
u = initial velocity
a = acceleration
t = time
v = 0 + 2.5(10)
v = 0 + 25
v = 25 m/s
Now, Distance travelled
v² - u² = 2as
(25)² - (0)² = 2(2.5)(s)
625 - 0 = 5s
625 = 5s
625/5 = s
125 = s
Hence
Final velocity is 25 m/s & Distance travelled is 125 m
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