Question

1. A car travels from a point A to point B at constant speed of 50 km/h. On return
journey along the same path, it travels at a constant speed of 40 km/h. Find its
distance travelled, displacement and average speed.
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Answer 1

Answer:

IF YOU HELPS THEN

Explanation:

Let the distance between A and B be x

Speed ¹ = 50kmph

therefore time taken = x/50

return journey

speed ²=40kmph

time taken = x/40

total distance travelled =x+x=2x km

displacement =0

average speed = total distance/total time

= 2x/(x/50+x/40)

= 2x÷[ x(40+50)/200]

= 2*200/90

= 45 kmph

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Answer 2

Answer:

let the distance be X km

time taken to go from A to B=X/50

time taken to go from B to A=X/40

distance travelled =2X km

displacement =0km

average speed =total distance /total time

=2X/(X/50+X/40)=2X/{(4X+5X)/200}

=2X/(9X/200)=2X×200/9X=44.44 km/h

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