1. A car travels from a point A to point B at constant speed of 50 km/h. On return
journey along the same path, it travels at a constant speed of 40 km/h. Find its
distance travelled, displacement and average speed.
Answers
Answered by
1
Let the distance between A and B be x
Speed ¹ = 50kmph
therefore time taken = x/50
return journey
speed ²=40kmph
time taken = x/40
total distance travelled =x+x=2x km
displacement =0
average speed = total distance/total time
= 2x/(x/50+x/40)
= 2x÷[ x(40+50)/200]
= 2*200/90
= 45 kmph
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Answered by
4
Answer:
total distansce coverd by car
Step-by-step explanation:
A to B = 50 km
return journey =40 km
so 50+40=90km
displacement
car travel A to B = 50 km
return journey =40km
50 - 40 = 10 km
Average speed = total area covered by object / total time taken by object
total time= 50 +40 =90
total time = 1hr +1hr
90 km/2 hr
=45 km
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