Question

1. A car travels from a point A to point b at constant speed of 5o km/h. On return journey along the same path, it travels at a constant speed of 40 km/h find its distance travelled, displacement and average speed​

Answer 1

Let the distance between A and B be x

Speed ¹ = 50kmph

therefore time taken = x/50

return journey

speed ²=40kmph

time taken = x/40

total distance travelled =x+x=2x km

displacement =0

average speed = total distance/total time

= 2x/(x/50+x/40)

= 2x÷[ x(40+50)/200]

= 2*200/90

= 45 kmph

please mark me brain mark list

Answer 2

SOLUTION → V1 = 50 km/hr. V2 = 40 km/hr

$vavg = 2x \div \frac{x}{50} + \frac{x}{40} \\ vavg = \frac{2 \times 50 \times 40}{90} = \frac{4000}{90} \\ = 44.45 \: kmph$

:)