Question

1. A ceramic tile measuring 10 cmx 10 cm has been designed to bear a pressure of 400 N/m2.Will it withstand a force of 5N?
2.A force of 10N acts on an area of 0.1m2.The force is kept the same but the area is reduced to half.
Which of the following is true?
i)pressure does not change. ii)pressure reduces to half iii)pressure increases by 1.5 times. Iv)pressure doubles



GUYS HELP

Answer 1

Answer(1):

• No, Tile will not withstand a force of 5 N.

Explanation(1):

Given that,

→ Area of ceramic tile = 10 cm × 10 cm

→ Area of ceramic tile = 100 cm²

→ Area of ceramic tile = 100/10000  m²

→ Area of ceramic tile = 0.01 m²

Also, given that tile can bear a maximum pressure of 400 N/m²

so,

Calculating the maximum force tile can bear

Using formula

→ Pressure = force / area

→ Force = Pressure × area

→ Force = 400 × 0.001

→ Force = 4 Newton

It means tile can bear a maximum force of 4 Newtons.

therefore,

• Tile will not withstand a force of 5 Newtons.

_____________________________

Answer(2):

• Option (iv) pressure doubles is true.

Explanation(2):

We are given that,

A force of 10 N acts on an area of 0.1 m².

so,

Calculating pressure

Using formula

→ Pressure = force / area

→ Pressure = 10 / 0.1

→ Pressure = 100 Pa

Now,

Given that force is kept same but the area is reduced to half

so,

→ New pressure = Force / new area

→ New pressure = 10 / ( 0.1 / 2 )

→ New pressure = 20 / 0.1

→ New pressure = 200 Pa

Therefore,

we can see that New pressure is double of initial one.

so,

• Option (iv) Pressure doubles is correct.

Answer 2

1)

Given:

• Area of tile = 10cm × 10cm
• Maximum pressure = 400 N/m²

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Need to find:

• Can it with stand a force of 5N?

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Solution:

Area= 10cm × 10cm

⟹ Area = 100 cm²

⟹ Area = 100 ÷ 10000 m²

⟹ Area = 0.01 m²

━━━━━━━━━━━━━━━

We know,

Pressure = Force ÷ Area

⟹ Force= Pressure × Area

⟹ Force = 400 × 0.01 N

⟹$\purple{\boxed{ Force = 4N}}$

This means the tile can withstand a maximum Force of 4N.

As 5N> 4N,

Thus $\red{\large{\bold{No!\:The\:Tile\:can't\:withstand}}}$ a force of 5N

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2)

Given :

• Force= 10N
• Area1= 0.1 m²
• Area2= (0.1÷2) m²

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Need to find:

• Change in Pressue =?

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Solution:

• Case 1:

Force = 10 N

Area= 0.1 m²

Then,

Pressure1= Force÷ Area

⟹ Pressure1= 10 ÷ 0.1 N/ m²

⟹$\purple{\boxed{\bold{ Pressure_{1}= 100 Pa}}}$

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• Case 2:

Force = 10N

Area = (0.1÷2) m²

⟹ Area = 0.05 m²

Now,

Pressure 2= Force ÷ Area

⟹ Pressure2= 10÷ 0.05 N/m²

⟹ Pressure2 = 1000÷5 Pa

⟹ $\purple{\boxed{\bold{Pressure_{2}= 200Pa}}}$

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Clearly Pressure2= 2× Pressure1

Thus $\huge{\red{\bold{\boxed{Option\:iv}}}}$ is correct$\large{\red{\bold{i.e.\:Pressure\: doubles}}}$