Physics, asked by dev0123456789dm, 9 months ago

1. A charge +q is fixed at each of the points x = x0, * = 3x0,
= 5x0 ... up to inf. on the x-axis and a charge -q is fixed at
each of the points x = 2x0, x = 4x0, x = 6x0 ... up to inf. Here
Xo is a positive constant. Take the electric potential at a point
due to a charge at a distance r from it to be Q/(411€or).
Then, the potential at the origin due to the above system of
charges is :
(a) zero
(b) 8Tɛox, loge 2
q loge 2
(c) o
(d
)
41E, X​

Answers

Answered by yatinsawhney20170824
0

Explanation:

burihej hehejepbjjbdk jdgkrk vejdhk gdjhdn dndv gen gnd bejb. hdhjehenn

Answered by nvpsk1975
0

Answer:

jglcjglcjlgoguipgihugiugc

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