Question

1. A chord is at a distance of 8 cm from the centre of circle of radius
17 cm the length of chord is
a. 25 cm
b. 12. 5 cm
c. 30 cm
d. 9 cm​

Answer 1

Step-by-step explanation:

Let AB be the chord with distance from the center =8 cm

OA=radius=17cm

Now, OC⊥AB

Then, AC=CB=2AB.......(i)....(perpendicular drawn from the centre of the circle to the chord bisects the chord)

Now, △ACO is right angled triangle at C

∴AC=(OA2−OC2)=(172−82)=(225)=15cm

Hence, AB=2×15=30cm ............ From (i)