Question

1.A chord is at a distance of 8cm from the center of a circle of radious 17cm. The length of the chord is?
♡25cm.
♡12.5cm.
♡30cm.
♡9cm.​

Answer 1

Answer:

3). 30cm

Step-by-step explanation:

Let AB be the chord with distance from the center =8 cm

Let AB be the chord with distance from the center =8 cmOA=radius=17cm

Now, OC⊥AB

Then, AC=CB=AB

2. ....(i)....(perpendicular

drawn from the centre of the circle to the chord bisects the chord)

Now, △ACO is right angled traingle at c

AC = √(OA² –OC²). = √(17²–8²)=√(225)=15cm

Hence,AB=2×15=30cm......from(1)

Answer 2

Answer:

= 30 cm.

Step-by-step explanation:

Let AB be the chord with distance from the center =8 cm

OA=radius=17cm

Now, OC⊥AB

Then, AC=CB= AB/2 .......(i)....(perpendicular drawn from the centre of the circle to the chord bisects the chord)

Now, △ACO is right angled triangle at C

∴AC=

$\sqrt{oa { }^{2} } - \sqrt{oc {}^{2} }$

=

$\sqrt{17 {}^{2} } - \sqrt{8 {}^{2} }$

=

$\sqrt{225}$

=15cm

Hence, AB=2×15=30cm ............from EQ(1)

⚕️ NONEXISTENT ⚕️