Question

1. A chord of length 6 cm is drawn in a circle
of radius 5 cm. Calculate its distance from the
centre of the circle.​

Answer 1

Answer:

4 cm

Step-by-step explanation:

Refer the attached figure

Length of Chord AB = 6 cm

Perpendicular Line form the center of the circle to the chord = OC

OB = OA = Radius of circle = 5 cm

Theorem : A perpendicular dropped from the center of the circle to a chord bisects it. It means that both the halves of the chords are equal in length.

So, OB bisects AB

So,

In ΔOCB

Hence distance of chord from the center of the circle is 4 cm.

Step-by-step explanation:

Refer the attached figure

Length of Chord AB = 6 cm

Perpendicular Line form the center of the circle to the chord = OC

OB = OA = Radius of circle = 5 cm

Theorem : A perpendicular dropped from the center of the circle to a chord bisects it. It means that both the halves of the chords are equal in length.

So, OB bisects AB

So,

In ΔOCB

Hence distance of chord from the center of the circle is 4 cm.

Answer 2

Hope it will help you