$1] A chord PQ of length 8 cm is drawn to a circle with centre 'O. The
perpendicular from O to the chord cuts the chord at 'R' and meets the
circle at 'S'. IF RS - 2 cm. Find the radius of the circle. OR
Answers
Answered by
0
Answer:
68^1/2
Step-by-step explanation:
we can form a right angle triangle as h^2=s^2+s^2
h^2 =8^2+2^2
h^2 =64+4
h^2=68
h=68^1/2
Similar questions