Question

(1) A circle is inscribed
in the quadrilateral PQRS.
Prove that:
QR + SP = QP+ SR​

Answer 1

By theorem 10.2

QC=QD (1)

RC=RB. (2)

SA= SB. (3)

PA= PD. (4)

ADDING ALL THE RESULTS,

QC+RC+SA+PA=QD+PD+RB+SB

QR+SP=QP+SR

Hence proved....

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