Question

1. A circular flower bed of circumference 352 m is surrounded by a path of width 4 m.
Find the circumference of the outer track of path. Also find the cost of fencing the
outer track at the rate of 6 per m. Also find the area of track. (HOT​

Answer 1

A circular bed (inner)circumference= 352m

width (given) = 4m

Circumference of inner track = 2πr

352m= 2×π×r

352/2=22/7r

176×7/22= r

inner radius= 56m

Outer radius= 56m+4m

=60m

circumference of outer track= 2πr

= 2×22/7×60

= 377.14m

Area of outer track= πr^2

= 22/7×60×60

=11314.28m^2

cost of fencing of outer track = 11314.28×6 rs.

= 67885.68 rs

area of Inner track= πr^2

=22/7×56×56

= 9856m^2

area of track= area of outer track - area of inner track

= (11314.28-9856)m^2

=1458.28 m^2

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