Question

1) A clerk writes 9 in place of 90.
D
... He committees an error of
%​

Answer 1

Step-by-step explanation:

solution:

correct value = 90

wrong value = 9

Difference = 90-9

= 81

% of error = Difference / correct value × 100

= 81/90×100

= 90%

Answer 2

Given,

A clerk writes 9 in place of 90

To Find,

He commits an error of = %?

Solution,

We can solve the question as follows:

It is given that a clerk wites 9 in place of 90. We have to find the percentage error.

The formula for percentage error of a quantity is given as:

$Percentage\: error = \frac{x - x'}{x} *100$

Where,

$x = The\: actual\: or\: value$

$x' = The\: incorrect\: value$

In the given question,

$x = 90$

$x' = 9$

Substituting the values in the above formula,

$Percentage\: error = \frac{90 - 9}{90}*100$

                           $= \frac{81}{90}*100$

                           $= 0.9*100$

                           $= 90$%

Hence, he commits an error of 90%.