Question

1 A code with Centre (3,2) passes through the point (6,3)
What is the radius of the circle?​

Answer 1

Step-by-step explanation:

Radius of the circle whose centre is (3,2) and passes through (−5,6) is the distance between (3,2) and (−5,6)

=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

=

(−5−3)

2

+(6−2)

2

=

(−8)

2

+(4)

2

=

64+16

=

80

=4

5

Units.