Question

1. A compound gave on analysis the following percentage composition K-26.27% [atomic mass of K=39], Cr-35.36% [atomic mass of Cr =52), and oxygen=38.07% [atomic mass of oxygen -16). Determine the empirical formula of the compound.

Answer 1

Answer:

K2Cr2O7

Explanation:

K. Cr. O

percentage=26.27. 35.36. 38.07

per./atomic= 0.67. 0.68 2.37

mass

DIVIDE ALL BY SIMPLEST VALUE

simplestratio= 1. 1.01=1 3.5

MULTIPLIED BY 2 WE GET WHOLE NUMBER RATIO

=2 2 7

EMPIRICAL FORMULA= K2Cr2O7

Answer 2

Explanation:

empherical formula=K2Cr2O7