Question

1
A conductor of length 3m moving in a uniform magnetic field of strength 100 T. It covers a distance
of 70 m in 5s. It's plane of motion makes an angle of 30" with direction of magnetic field. Calculate
the emf induced in it.​

Answer 1

Answer:

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Answer 2

Answer:

use formula, \xi=\vec{v}\times\vec{B}.\vec{dl}ξ=

v

×

B

.

dl

where \xiξ denotes induced emf, v denotes velocity of conductor, B denotes magnetic field intensity and dl denotes length of conductor.

here, angle between plane of motion of conductor and magnetic field intensity is 30° , B = 100T, v = 70/5 = 14m/s and dl = 3cm = 0.03m

so, \xi=|\vec{v}||\vec{B}|sin30^{\circ}|\vec{dl}|ξ=∣

v

∣∣

B

∣sin30

∘

∣

dl

∣

= 14 × 100 × sin30° × 0.03

= 14 × 3 × sin30°

= 21 volts

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