Question

1. A constant force F is applied on a body of
mass 5 kg, changes its velocity from 2 m/s
to 7 m/s in 10 second. If the direction of
motion is unchanged, then the applied
force is​

Answer 1

Explanation:

F=ma

m=5kg

u=2m/s

v=7m/s

t=10s

a=v-u/t

a=7-2/10

a=5/10

a=0.5m/s²

F=5(0.5)

F=2.5 Newton

Answer 2

Answer:

2.5 N

Explanation:

F = ma

$= m( \frac{v - u}{t} )$

$= 5( \frac{7 - 2}{10} )$

$= 5 \times \frac{5}{10}$

$= 5 \times \frac{1}{2}$

= 5/2 Kgm/s^2

= 2.5 N