Question

-1) A constant force is applied on 10kg
mess at rest. The ratio of worksdone
let, and and 3nd Seconds is
in 1st, 2nd, 3rdsec will be​

Answer 1

Answer:

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Explanation:

Let the force be F.

Distance travelled in the nth second=S

n

=u+

2

1

a(2n−1)

Acceleration=a=

10

F

S

1

=

2

1

×

10

F

×(2×1−1)=

20

F

S

2

=

2

1

×

10

F

×(2×2−1)=

20

3F

S

3

=

2

1

×

10

F

×(2×3−1)=

4

F

So ratio=

20

F

:

20

3F

:

4

F

=

20

1

:

20

3

:

4

1

=1:3:5

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