Question

1) A contract on construction job specifies a penalty for delay of completion beyond a

certain date as follows: ` 200 for the first day, ` 250 for the second day, ` 300 for the third

day, etc., the penalty for each succeeding day being ` 50 more than for the preceding day.

How much money the contractor has to pay as penalty, if he has delayed the work by 30
days?

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Answer 1

Answer:

First generate a series 200+250+300+350+....

Step-by-step explanation:

And now applying the of Arithmetic Progression, find out the sum of first 30 terms.

And it's the required answer.

I didn't solve it here, so that you get the process.

Thanks.