1. A crane lifts a weight of 3500 N through a vertical height of 0.2 km
a. What is the work done by the crane?
b. What is the GPE of the weight at the top of 0.2 km, assuming there in no loss of energy?
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Explanation:
WORK=mgh (when there is a height)
=3500×10×0.2×10³
=35000×200
=7000000
=7×10⁶
=7 MJ (7 mega joules)
GPE= IS ALSO mgh
SO, IT IS ALSO 7 MJ
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