Question

1. A cricket ball of mass 150 g moving with a velocity of 15 ms-1 is brought to rest by a player in 0.05 s. Calculate the impulse.​

Answer 1

Answer:

impulse= mv

impulse= mv=150 X 15 X 100

impulse= mv=150 X 15 X 100=22500 Ns [Answer]

v=u+at

v=u+atu/t=a

v=u+atu/t=a=15/0.5

v=u+atu/t=a=15/0.5=30 m/s^2

v=u+atu/t=a=15/0.5=30 m/s^2f=ma

v=u+atu/t=a=15/0.5=30 m/s^2f=ma=150 X 30/1000

v=u+atu/t=a=15/0.5=30 m/s^2f=ma=150 X 30/1000=4.5 N [Answer]