Question

1. A cylindrical tub of radius 5cm and length 9.8cm is full of water. A solid in the form of
a right circular cone mounted on a hemisphere is immersed into the tub. If the radius of
the hemisphere is 3.5 cm and height of cone outside the hemisphere is 5cm find the
volume of water left in the tub.​

Answer 1

Answer:

Step-by-step explanation:

tub is half of a cylinder

∴ volume of water = 1/2 x 22/7 x 5² x 9.8 = 385 cm³

Volume of the solid = volume of cone + volume of hemisphere

= 1/3 x 22/7 x 3.5² x 5 + 2/3 x 22/7 x 3.5³

= 64 1/6 + 89 5/6

= 154 cm³

Remaining volume = 385 - 154 = 231 cm³